4x^2+12x-35=5

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Solution for 4x^2+12x-35=5 equation:


Simplifying
4x2 + 12x + -35 = 5

Reorder the terms:
-35 + 12x + 4x2 = 5

Solving
-35 + 12x + 4x2 = 5

Solving for variable 'x'.

Reorder the terms:
-35 + -5 + 12x + 4x2 = 5 + -5

Combine like terms: -35 + -5 = -40
-40 + 12x + 4x2 = 5 + -5

Combine like terms: 5 + -5 = 0
-40 + 12x + 4x2 = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(-10 + 3x + x2) = 0

Factor a trinomial.
4((-5 + -1x)(2 + -1x)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(-5 + -1x)' equal to zero and attempt to solve: Simplifying -5 + -1x = 0 Solving -5 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1x = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1x = 0 + 5 -1x = 0 + 5 Combine like terms: 0 + 5 = 5 -1x = 5 Divide each side by '-1'. x = -5 Simplifying x = -5

Subproblem 2

Set the factor '(2 + -1x)' equal to zero and attempt to solve: Simplifying 2 + -1x = 0 Solving 2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1x = 0 + -2 -1x = 0 + -2 Combine like terms: 0 + -2 = -2 -1x = -2 Divide each side by '-1'. x = 2 Simplifying x = 2

Solution

x = {-5, 2}

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